What is partialfraction (x^2)/(1-x) ?

The solution to partialfraction (x^2)/(1-x) is -x-1+1/(-x+1)

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partialfraction (x^2)/(1-x)

partial fractions

\frac{x ^{2}}{1 - x}

- x - 1 + \frac{1}{- x + 1}

Solution steps

\frac{x ^{2}}{1 - x}

Long division

\frac{x ^{2}}{1 - x} : - x - 1 + \frac{1}{- x + 1}

= - x - 1 + \frac{1}{- x + 1}

- x - 1 + \frac{1}{- x + 1}

y^{^{''}} + 3 y^{^{'}} - 10 y = 6 e^{4 x}

\int \frac{x}{x - 9} d x

x y^{2} y^{^{'}} = x^{3} + 2 y^{3}

\frac{d}{d x} (\frac{2 x}{3 x ^{2} - 3})

t an g e n t f (x) = 6 x, at x = 9

What is partialfraction (x^2)/(1-x) ?
The solution to partialfraction (x^2)/(1-x) is -x-1+1/(-x+1)