What is the limit as x approaches-1 of ln(x) ?

The limit as x approaches-1 of ln(x) is Does not exist

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limit as x approaches-1 of ln(x)

x \to - 1 lim (ln (x))

Does not exist

Solution steps

x \to - 1 lim (ln (x))

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (ln (x)) =

Does not exist

x \to - 1 + lim (ln (x)) =

Does not exist

= Does not exist

d er i v a t i v e y = sin^{2} (x^{3})

h \to 0 lim (\frac{( h - 3 ) ^{2} - 9}{h})

t a y l or 8 + x^{2}, 1

f (x) = 4 x^{5} ln (x)

ma c l a u r in ln (1 - x^{2})

What is the limit as x approaches-1 of ln(x) ?
The limit as x approaches-1 of ln(x) is Does not exist