What is the limit as h approaches 0 of ((h-3)^2-9)/h ?

The limit as h approaches 0 of ((h-3)^2-9)/h is -6

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limit as h approaches 0 of ((h-3)^2-9)/h

h \to 0 lim (\frac{( h - 3 ) ^{2} - 9}{h})

- 6

Solution steps

h \to 0 lim (\frac{( h - 3 ) ^{2} - 9}{h})

Simplify

\frac{( h - 3 ) ^{2} - 9}{h} : h - 6

= h \to 0 lim (h - 6)

Plug in the value

h = 0

= 0 - 6

Simplify

= - 6

t a y l or 8 + x^{2}, 1

f (x) = 4 x^{5} ln (x)

ma c l a u r in ln (1 - x^{2})

\int t^{2} e^{\frac{t}{3}} d t

x \to \infty lim (\frac{( e ^{- x y - x + y} )}{x ^{2} y ^{2} + x y})

What is the limit as h approaches 0 of ((h-3)^2-9)/h ?
The limit as h approaches 0 of ((h-3)^2-9)/h is -6