What is the derivative of 2e^x+e^xx ?

The derivative of 2e^x+e^xx is e^xx+3e^x

What is the first derivative of 2e^x+e^xx ?

The first derivative of 2e^x+e^xx is e^xx+3e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (2 e^{x} + e^{x} x)

e^{x} x + 3 e^{x}

Solution steps

\frac{d}{d x} (2 e^{x} + e^{x} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) + \frac{d}{d x} (e^{x} x)

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d}{d x} (e^{x} x) = e^{x} x + e^{x}

= 2 e^{x} + e^{x} x + e^{x}

Simplify

= e^{x} x + 3 e^{x}

y^{^{'}} = 20 x y

\frac{d}{d x} (\frac{x}{x - 6})

\int \frac{1}{4} x^{2} d x

l a pl a ce t r an s f or m 6 e^{- 5 t} + 5 t

d er i v a t i v e y = \frac{3 x ^{4} + 9}{x ^{2}}

What is the derivative of 2e^x+e^xx ?
The derivative of 2e^x+e^xx is e^xx+3e^x
What is the first derivative of 2e^x+e^xx ?
The first derivative of 2e^x+e^xx is e^xx+3e^x