What is the integral of (cos^2(y))/(1-sin(y)) ?

The integral of (cos^2(y))/(1-sin(y)) is -cos(y)+y+C

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integral of (cos^2(y))/(1-sin(y))

\int \frac{cos ^{2} ( y )}{1 - sin ( y )} d y

- cos (y) + y + C

Solution steps

\int \frac{cos ^{2} ( y )}{1 - sin ( y )} d y

Rewrite using trig identities

= \int sin (y) + 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (y) d y + \int 1 d y

\int sin (y) d y = - cos (y)

\int 1 d y = y

= - cos (y) + y

Add a constant to the solution

= - cos (y) + y + C

\int 3 cos (x) d x

\int (\frac{x ^{2}}{9 - x ^{2}}) d x

\frac{d}{d x} (\frac{( 2 x ^{3} + a x + a )}{x ^{2} - 1})

\int 4 x^{2} e^{x^{3}} d x

\frac{d}{d x} (\frac{x ^{2}}{8 - 8 x})

What is the integral of (cos^2(y))/(1-sin(y)) ?
The integral of (cos^2(y))/(1-sin(y)) is -cos(y)+y+C