What is the derivative of y=4cot(3-2x) ?

The derivative of y=4cot(3-2x) is 8csc^2(3-2x)

What is the first derivative of y=4cot(3-2x) ?

The first derivative of y=4cot(3-2x) is 8csc^2(3-2x)

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derivative of

y = 4 cot (3 - 2 x)

8 csc^{2} (3 - 2 x)

Solution steps

\frac{d}{d x} (4 cot (3 - 2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cot (3 - 2 x))

Apply the chain rule:

- csc^{2} (3 - 2 x) \frac{d}{d x} (3 - 2 x)

= - csc^{2} (3 - 2 x) \frac{d}{d x} (3 - 2 x)

\frac{d}{d x} (3 - 2 x) = - 2

= 4 (- csc^{2} (3 - 2 x) (- 2))

Simplify

= 8 csc^{2} (3 - 2 x)

\int_{0}^{2} (4 x - 2 x^{2}) d x

\frac{d y}{d x} y = (x^{2} + 3 x)^{2}

x \to - \infty lim (\frac{4}{x})

\int \frac{cos ( x )}{sin ^{2} ( x ) - 4} d x

\int 4 sec^{4} (x) d x

What is the derivative of y=4cot(3-2x) ?
The derivative of y=4cot(3-2x) is 8csc^2(3-2x)
What is the first derivative of y=4cot(3-2x) ?
The first derivative of y=4cot(3-2x) is 8csc^2(3-2x)