(40cos(20t-pi/2))^'

解

(40 cos (20 t - \frac{π}{2}))^{^{'}}

800 cos (20 t)

解答ステップ

(40 cos (20 t - \frac{π}{2}))^{'}

簡素化

40 cos (20 t - \frac{π}{2}) : 40 sin (20 t)

= (40 sin (20 t))^{^{'}}

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 40 (sin (20 t))^{^{'}}

連鎖法則を適用:

cos (20 t) (20 t)^{'}

= cos (20 t) (20 t)^{'}

(20 t)^{'} = 20

= 40 cos (20 t) \cdot 20

簡素化

= 800 cos (20 t)