y^{''}+y^'=2e^x+14

Lösung

y^{^{''}} + y^{^{'}} = 2 e^{x} + 14

y = c_{1} + c_{2} e^{- x} + e^{x} + 14 x

Schritte zur Lösung

y^{''} (x) + y^{'} (x) = 2 e^{x} + 14

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + e^{x} + 14 x

y = c_{1} + c_{2} e^{- x} + e^{x} + 14 x

x \to - 3 lim (\frac{x}{x + 5})

\frac{d}{d x} (\frac{1}{3 x ^{2} + x + 1})

\frac{d y}{d x} = \frac{x ^{4} y ^{4} + 4 x ^{4}}{y ^{3}}

\int \frac{1}{x ^{3} 4 x ^{2} - 9} d x

x \to 0 lim (\frac{sin ( 15 x )}{x})