derivative cos(2x)-2xsin(2x)

Lösung

ableitung von

cos (2 x) - 2 x sin (2 x)

- 4 sin (2 x) - 4 x cos (2 x)

Schritte zur Lösung

\frac{d}{d x} (cos (2 x) - 2 x sin (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (2 x)) - \frac{d}{d x} (2 x sin (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

\frac{d}{d x} (2 x sin (2 x)) = 2 (sin (2 x) + 2 x cos (2 x))

= - sin (2 x) \cdot 2 - 2 (sin (2 x) + 2 x cos (2 x))

Vereinfache

- sin (2 x) \cdot 2 - 2 (sin (2 x) + 2 x cos (2 x)) : - 4 sin (2 x) - 4 x cos (2 x)

= - 4 sin (2 x) - 4 x cos (2 x)

y^{^{''}} - 4 y^{^{'}} = 3 t

\int \frac{x + 18}{x ^{2} + 6 x + 13} d x

\int_{0}^{\infty} x^{0} e^{- x} d x

\frac{\partial}{\partial x} (x y (4 - y))

\frac{\partial}{\partial x} (\frac{y}{x} ln (x))