derivative of (4x^2+6x+8/(sqrt(x)))

Lösung

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 8}{x})

\frac{6 x ^{2} + 3 x - 4}{x x}

Schritte zur Lösung

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 8}{x})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{2} + 6 x + 8 ) x - \frac{d}{d x} ( x ) ( 4 x ^{2} + 6 x + 8 )}{( x ) ^{2}}

\frac{d}{d x} (4 x^{2} + 6 x + 8) = 8 x + 6

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{( 8 x + 6 ) x - \frac{1}{2 x} ( 4 x ^{2} + 6 x + 8 )}{( x ) ^{2}}

Vereinfache

\frac{( 8 x + 6 ) x - \frac{1}{2 x} ( 4 x ^{2} + 6 x + 8 )}{( x ) ^{2}} : \frac{6 x ^{2} + 3 x - 4}{x x}

= \frac{6 x ^{2} + 3 x - 4}{x x}

\frac{d}{d y} (x^{2} - x y + 2)

d er i v a t i v e y = \frac{5 + x f ( x )}{x}

\int 9 x^{4} d x

y^{^{'}} + 2 x y = 2 x e^{- x^{2}}

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}