What is the integral of (3x^2+2)/(x^2) ?

The integral of (3x^2+2)/(x^2) is -(3x^2+2)/x+6x+C

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integral of (3x^2+2)/(x^2)

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

- \frac{3 x ^{2} + 2}{x} + 6 x + C

Solution steps

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

Apply Integration By Parts

= - \frac{3 x ^{2} + 2}{x} - \int - 6 d x

\int - 6 d x = - 6 x

= - \frac{3 x ^{2} + 2}{x} - (- 6 x)

Simplify

= - \frac{3 x ^{2} + 2}{x} + 6 x

Add a constant to the solution

= - \frac{3 x ^{2} + 2}{x} + 6 x + C

\int 30 d x

n = 0 \sum \infty \frac{1}{ln ( n )}

d er i v a t i v e y = - 0.0959 x^{2} + 106.83 x + 71149

\int 3 2 - 5 x^{2} (- 10 x) d x

\int_{1}^{R} x^{- \frac{9}{5}} d x

What is the integral of (3x^2+2)/(x^2) ?
The integral of (3x^2+2)/(x^2) is -(3x^2+2)/x+6x+C