What is the derivative of 8x^2sin(x)tan(x) ?

The derivative of 8x^2sin(x)tan(x) is 8(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)

What is the first derivative of 8x^2sin(x)tan(x) ?

The first derivative of 8x^2sin(x)tan(x) is 8(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)

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derivative of

8 x^{2} sin (x) tan (x)

8 (2 x sin (x) tan (x) + sin (x) (1 + sec^{2} (x)) x^{2})

Solution steps

\frac{d}{d x} (8 x^{2} sin (x) tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{2} sin (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (x) tan (x)

= 8 (\frac{d}{d x} (x^{2}) sin (x) tan (x) + \frac{d}{d x} (sin (x) tan (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x) tan (x)) = sin (x) (1 + sec^{2} (x))

= 8 (2 x sin (x) tan (x) + sin (x) (1 + sec^{2} (x)) x^{2})

\frac{d}{d x} (10000 (12 + x) e^{- 0.05 x})

t an g e n t f (x) = - 4 x^{2} - 5 x + 2

\int_{0}^{π} x cos (3 x) d x

\int \frac{y ^{2} + 2 y + 1}{( y ^{2} + 1 ) ^{2}} d y

4 y^{^{''}} + 28 y^{^{'}} + 49 y = 0

What is the derivative of 8x^2sin(x)tan(x) ?
The derivative of 8x^2sin(x)tan(x) is 8(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)
What is the first derivative of 8x^2sin(x)tan(x) ?
The first derivative of 8x^2sin(x)tan(x) is 8(2xsin(x)tan(x)+sin(x)(1+sec^2(x))x^2)