zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

integral of 6x^5sqrt(3x^4+2)

解答

\int 6 x^{5} 3 x^{4} + 2 d x

解答

- \frac{1}{4} x^{2} 2 + 3 x^{4} - \frac{1}{2 3} ln \frac{3}{2} x^{2} + \frac{1}{2} (2 + 3 x^{4}) + \frac{1}{4} x^{2} (3 x^{4} + 2)^{\frac{3}{2}} + C

求解步骤

\int 6 x^{5} 3 x^{4} + 2 d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x^{5} 3 x^{4} + 2 d x

使用换元积分法

= 6 \cdot \int \frac{u ^{2} 3 u ^{2} + 2}{2} d u

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{2} \cdot \int u^{2} 3 u^{2} + 2 d u

使用三角换元法

= 6 \cdot \frac{1}{2} \cdot \int \frac{4}{3 3} sec^{3} (v) tan^{2} (v) d v

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} \cdot \int sec^{3} (v) tan^{2} (v) d v

使用三角恒等式改写

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} \cdot \int sec^{3} (v) (- 1 + sec^{2} (v)) d v

乘开

sec^{3} (v) (- 1 + sec^{2} (v)) : - sec^{3} (v) + sec^{5} (v)

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} \cdot \int - sec^{3} (v) + sec^{5} (v) d v

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} (- \int sec^{3} (v) d v + \int sec^{5} (v) d v)

\int sec^{3} (v) d v = \frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣

\int sec^{5} (v) d v = \frac{sec ^{4} ( v ) sin ( v )}{4} + \frac{3}{4} (\frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣)

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} (- (\frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣) + \frac{sec ^{4} ( v ) sin ( v )}{4} + \frac{3}{4} (\frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣))

代回

= 6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} - (\frac{1}{2} sec (arctan (\frac{3}{2} x^{2})) tan (arctan (\frac{3}{2} x^{2})) + \frac{1}{2} ln tan (arctan (\frac{3}{2} x^{2})) + sec (arctan (\frac{3}{2} x^{2}))) + \frac{sec ^{4} ( arctan ( \frac{3}{2} x ^{2} ) ) sin ( arctan ( \frac{3}{2} x ^{2} ) )}{4} + \frac{3}{4} (\frac{1}{2} sec (arctan (\frac{3}{2} x^{2})) tan (arctan (\frac{3}{2} x^{2})) + \frac{1}{2} ln tan (arctan (\frac{3}{2} x^{2})) + sec (arctan (\frac{3}{2} x^{2})))

化简

6 \cdot \frac{1}{2} \cdot \frac{4}{3 3} - (\frac{1}{2} sec (arctan (\frac{3}{2} x^{2})) tan (arctan (\frac{3}{2} x^{2})) + \frac{1}{2} ln tan (arctan (\frac{3}{2} x^{2})) + sec (arctan (\frac{3}{2} x^{2}))) + \frac{sec ^{4} ( arctan ( \frac{3}{2} x ^{2} ) ) sin ( arctan ( \frac{3}{2} x ^{2} ) )}{4} + \frac{3}{4} (\frac{1}{2} sec (arctan (\frac{3}{2} x^{2})) tan (arctan (\frac{3}{2} x^{2})) + \frac{1}{2} ln tan (arctan (\frac{3}{2} x^{2})) + sec (arctan (\frac{3}{2} x^{2}))) : - \frac{1}{4} x^{2} 2 + 3 x^{4} - \frac{1}{2 3} ln \frac{3}{2} x^{2} + \frac{1}{2} (2 + 3 x^{4}) + \frac{1}{4} x^{2} (3 x^{4} + 2)^{\frac{3}{2}}

= - \frac{1}{4} x^{2} 2 + 3 x^{4} - \frac{1}{2 3} ln \frac{3}{2} x^{2} + \frac{1}{2} (2 + 3 x^{4}) + \frac{1}{4} x^{2} (3 x^{4} + 2)^{\frac{3}{2}}

解答补常数

= - \frac{1}{4} x^{2} 2 + 3 x^{4} - \frac{1}{2 3} ln \frac{3}{2} x^{2} + \frac{1}{2} (2 + 3 x^{4}) + \frac{1}{4} x^{2} (3 x^{4} + 2)^{\frac{3}{2}} + C

作图

流行的例子

derivative of 1/27 (x^5+2x^3)

\frac{d}{d x} (\frac{1}{27} (x^{5} + 2 x^{3}))

integral of sqrt(26x-x^2)

\int 26 x - x^{2} d x

integral from 0 to 2pi of sin^2(7x)

\int_{0}^{2 π} sin^{2} (7 x) d x

integral from 0 to sin(x) of 4sqrt(t)

\int_{0}^{s i n (x)} 4 t d t

7x(x+5y)((dy)/(dx))=7y(x-5y)

7 x (x + 5 y) (\frac{d y}{d x}) = 7 y (x - 5 y)