derivative of 1/27 (x^5+2x^3)

Lösung

\frac{d}{d x} (\frac{1}{27} (x^{5} + 2 x^{3}))

\frac{1}{27} (5 x^{4} + 6 x^{2})

Schritte zur Lösung

\frac{d}{d x} (\frac{1}{27} (x^{5} + 2 x^{3}))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{27} \frac{d}{d x} (x^{5} + 2 x^{3})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{27} (\frac{d}{d x} (x^{5}) + \frac{d}{d x} (2 x^{3}))

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= \frac{1}{27} (5 x^{4} + 6 x^{2})

\int 26 x - x^{2} d x

\int_{0}^{2 π} sin^{2} (7 x) d x

\int_{0}^{s i n (x)} 4 t d t

7 x (x + 5 y) (\frac{d y}{d x}) = 7 y (x - 5 y)

in v erse l a pl a ce \frac{1}{s ( s ^{2} + 36 )}