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Popular Calculus >

(2x+e^y)dx+xe^ydy=0

Solution

(2 x + e^{y}) d x + x e^{y} d y = 0

Solution

y = ln (\frac{c _{1}}{x} - x)

Solution steps

(2 x + e^{y}) d x + x e^{y} d y = 0

Solve exact ODE:

y = ln (\frac{c _{1}}{x} - x)

y = ln (\frac{c _{1}}{x} - x)

Graph

Popular Examples

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\int \frac{11 x ^{3}}{2 + x ^{2}} d x

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\frac{d}{d x} (ln (x^{- 1}))

\frac{d}{d u} (tan (u))

derivative of sin(x^{2x})

\frac{d}{d x} (sin (x^{2 x}))

Frequently Asked Questions (FAQ)

What is the solution for (2x+e^y)dx+xe^ydy=0 ?
The solution for (2x+e^y)dx+xe^ydy=0 is y=ln((c_{1})/x-x)