What is the integral from 1 to 2 of (1/(x^2)) ?

The integral from 1 to 2 of (1/(x^2)) is 1/2

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integral from 1 to 2 of (1/(x^2))

\int_{1}^{2} (\frac{1}{x ^{2}}) d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{1}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

= [- \frac{1}{x}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int - \frac{1}{1 + 2 x} d x

\int_{1}^{8} 1 + 3 x d x

\int (x^{2} - 3 x + 6) d x

\frac{d}{d x} (x^{2} - 3 x - 4)

\frac{d}{d x} (A e^{3 x} + 3 A x e^{3 x})

What is the integral from 1 to 2 of (1/(x^2)) ?
The integral from 1 to 2 of (1/(x^2)) is 1/2