What is the derivative of x^2-3x-4 ?

The derivative of x^2-3x-4 is 2x-3

What is the first derivative of x^2-3x-4 ?

The first derivative of x^2-3x-4 is 2x-3

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\frac{d}{d x} (x^{2} - 3 x - 4)

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x - 3 - 0

Simplify

= 2 x - 3

\frac{d}{d x} (A e^{3 x} + 3 A x e^{3 x})

\frac{\partial}{\partial x} (x cos (y - x))

\int_{- 3}^{0} \frac{1}{9 - x ^{2}} d x

\int_{0}^{20} cos (π x) d x

x \to 0 lim (\frac{x ^{2}}{x})

What is the derivative of x^2-3x-4 ?
The derivative of x^2-3x-4 is 2x-3
What is the first derivative of x^2-3x-4 ?
The first derivative of x^2-3x-4 is 2x-3