What is the derivative of f(x)=x^2-4x+3 ?

The derivative of f(x)=x^2-4x+3 is 2x-4

What is the first derivative of f(x)=x^2-4x+3 ?

The first derivative of f(x)=x^2-4x+3 is 2x-4

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derivative of

f (x) = x^{2} - 4 x + 3

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\int ((sec (x))^{2} - csc (x) cot (x)) d x

\int sin (x) \cdot sin (3 x) d x

\int 2 cos^{2} (2 x) d x

d er i v a t i v e s (t) = 4 e^{- 2 t} sin (2 π t)

y^{^{'}} = 1 - 100 (y - t)

What is the derivative of f(x)=x^2-4x+3 ?
The derivative of f(x)=x^2-4x+3 is 2x-4
What is the first derivative of f(x)=x^2-4x+3 ?
The first derivative of f(x)=x^2-4x+3 is 2x-4