What is the derivative of f(x)=9sin(3x) ?

The derivative of f(x)=9sin(3x) is 27cos(3x)

What is the first derivative of f(x)=9sin(3x) ?

The first derivative of f(x)=9sin(3x) is 27cos(3x)

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derivative of

f (x) = 9 sin (3 x)

27 cos (3 x)

Solution steps

\frac{d}{d x} (9 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 9 cos (3 x) \cdot 3

Simplify

= 27 cos (3 x)

\int_{0}^{5} 3 f (x) d x

\int x^{3} 1 + x^{2} d x

\frac{d}{d x} (2 A x)

y^{^{'}} = 2 y - 3 y^{2}

s l o p e in t erce pt (2.8) (0.6)

What is the derivative of f(x)=9sin(3x) ?
The derivative of f(x)=9sin(3x) is 27cos(3x)
What is the first derivative of f(x)=9sin(3x) ?
The first derivative of f(x)=9sin(3x) is 27cos(3x)