What is integral from 0 to 5 of 3f(x) ?

The answer to integral from 0 to 5 of 3f(x) is (75f)/2

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integral from 0 to 5 of 3f(x)

\int_{0}^{5} 3 f (x) d x

\frac{75 f}{2}

Solution steps

\int_{0}^{5} 3 f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 f \cdot \int_{0}^{5} x d x

Apply the Power Rule

= 3 f [\frac{x ^{2}}{2}]_{0}^{5}

Compute the boundaries:

\frac{25}{2}

= 3 f \frac{25}{2}

Simplify

= \frac{75 f}{2}

\int x^{3} 1 + x^{2} d x

\frac{d}{d x} (2 A x)

y^{^{'}} = 2 y - 3 y^{2}

s l o p e in t erce pt (2.8) (0.6)

d er i v a t i v e f (x) = \frac{x}{8 x ^{3} - 2 x + 9}

What is integral from 0 to 5 of 3f(x) ?
The answer to integral from 0 to 5 of 3f(x) is (75f)/2