What is the derivative of (64/x) ?

The derivative of (64/x) is -(64)/(x^2)

What is the first derivative of (64/x) ?

The first derivative of (64/x) is -(64)/(x^2)

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\frac{d}{d x} (\frac{64}{x})

- \frac{64}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{64}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 64 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 64 (- 1 \cdot x^{- 1 - 1})

Simplify

64 (- 1 \cdot x^{- 1 - 1}) : - \frac{64}{x ^{2}}

= - \frac{64}{x ^{2}}

t an g e n t f (x) = 8 x^{2} + 5 x, at x = 3

x \to 1.001 lim (x^{2} - 2 x - 1)

\int e^{x} 5 - e^{x} d x

\int e^{- 4 x} \cdot x d x

d er i v a t i v e 2 x^{2} + 15

What is the derivative of (64/x) ?
The derivative of (64/x) is -(64)/(x^2)
What is the first derivative of (64/x) ?
The first derivative of (64/x) is -(64)/(x^2)