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面积 x+1=y^2,y^2+2x=10

解答

面积

x + 1 = y^{2}, y^{2} + 2 x = 10

解答

无解

求解步骤

对于

x + 1 = y^{2}

将

y

移到一边:

y = x + 1, y = - x + 1

对于

y^{2} + 2 x = 10

将

y

移到一边:

y = 10 - 2 x, y = - 10 - 2 x

f_{1} (x) = x + 1

f_{2} (x) = - x + 1

要找到相交点，解

f_{i} (x) = f_{j} (x)

x + 1 = - x + 1 : x = - 1

x + 1 = 10 - 2 x : x = 3

x + 1 = - 10 - 2 x : x \in R

无解

- x + 1 = 10 - 2 x : x \in R

无解

- x + 1 = - 10 - 2 x : x = 3

10 - 2 x = - 10 - 2 x : x = 5

曲线没有界限

= 无解

作图

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