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Popular Calculus >

derivative of sqrt(3x^2+4)

Solution

\frac{d}{d x} (3 x^{2} + 4)

Solution

\frac{3 x}{3 x ^{2} + 4}

Solution steps

\frac{d}{d x} (3 x^{2} + 4)

Apply the chain rule:

\frac{1}{2 3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

= \frac{1}{2 3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

\frac{d}{d x} (3 x^{2} + 4) = 6 x

= \frac{1}{2 3 x ^{2} + 4} \cdot 6 x

Simplify

\frac{1}{2 3 x ^{2} + 4} \cdot 6 x : \frac{3 x}{3 x ^{2} + 4}

= \frac{3 x}{3 x ^{2} + 4}

Graph

Popular Examples

derivative of sqrt(4cos(x)+12x)

d er i v a t i v e 4 cos (x) + 12 x

tangent of f(x)=8sqrt(x)-3,\at x=64

t an g e n t f (x) = 8 x - 3, at x = 64

\frac{d}{d y} (y x^{2})

y^{''}+11y^'+22y=3468e^{2t}cos(12t)

y^{^{''}} + 11 y^{^{'}} + 22 y = 3468 e^{2 t} cos (12 t)

2y(dy)/(dx)+y^2cot(x)=csc(x)

2 y \frac{d y}{d x} + y^{2} cot (x) = csc (x)

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(3x^2+4) ?
The derivative of sqrt(3x^2+4) is (3x)/(sqrt(3x^2+4))
What is the first derivative of sqrt(3x^2+4) ?
The first derivative of sqrt(3x^2+4) is (3x)/(sqrt(3x^2+4))