What is the solution for 2(12)(18)+2(9)(dy)/(dt)=0 ?

The solution for 2(12)(18)+2(9)(dy)/(dt)=0 is y=-24t+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2(12)(18)+2(9)(dy)/(dt)=0

2 (12) (18) + 2 (9) \frac{d y}{d t} = 0

y = - 24 t + c_{1}

Solution steps

2 (12) (18) + 2 (9) \frac{d y}{d t} = 0

Substitute

\frac{d y}{d t}

with

y^{'} (t)

2 (12) (18) + 2 (9) y^{^{'}} (t) = 0

Isolate

y^{'} (t) : y^{'} (t) = - 24

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 24 d t

\int - 24 d t = - 24 t + c_{1}

y = - 24 t + c_{1}

\frac{d y}{d t} = 25 t^{4}

y^{^{'}} = \frac{6 x - 12}{x ^{2}}, y (1) = 20

\int 2 x ln (x^{2}) d x

\int \frac{cos ^{3} ( x )}{sin ^{2} ( x )} d x

\frac{\partial}{\partial x} ((\frac{x + 2}{y + 1})^{\frac{1}{2}})

What is the solution for 2(12)(18)+2(9)(dy)/(dt)=0 ?
The solution for 2(12)(18)+2(9)(dy)/(dt)=0 is y=-24t+c_{1}