en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

(dy)/(dt)=25t^4

Solution

\frac{d y}{d t} = 25 t^{4}

Solution

y = 5 t^{5} + c_{1}

Solution steps

\frac{d y}{d t} = 25 t^{4}

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = 25 t^{4}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 25 t^{4} d t

\int 25 t^{4} d t = 5 t^{5} + c_{1}

y = 5 t^{5} + c_{1}

Graph

Popular Examples

y^'=(6x-12)/(x^2),y(1)=20

y^{^{'}} = \frac{6 x - 12}{x ^{2}}, y (1) = 20

integral of 2xln(x^2)

\int 2 x ln (x^{2}) d x

integral of (cos^3(x))/(sin^2(x))

\int \frac{cos ^{3} ( x )}{sin ^{2} ( x )} d x

(\partial)/(\partial x)(((x+2)/(y+1))^{1/2})

\frac{\partial}{\partial x} ((\frac{x + 2}{y + 1})^{\frac{1}{2}})

laplacetransform e^{as}

l a pl a ce t r an s f or m e^{a s}

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=25t^4 ?
The solution for (dy)/(dt)=25t^4 is y=5t^5+c_{1}