What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 ?

The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 is y=(2sin(x))/(cos(x))+1-2/(cos(x))

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(sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0, y (0) = - 1

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

Solution steps

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

d er i v a t i v e f (x) = x^{2} - 5 x + 5

s l o p e y = 9 + 5 x^{2} - 2 x^{3}

\frac{\partial}{\partial x} (\frac{x}{1 + x ^{2} + y ^{2}})

a re a y = 4 x^{2}, y = 4

\int \frac{2 x - 3}{x ^{2} + 6 x + 4} d x

What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 ?
The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 is y=(2sin(x))/(cos(x))+1-2/(cos(x))