25y^{''}+3y=0

Lösung

25 y^{^{''}} + 3 y = 0

y = c_{1} cos (\frac{3 t}{5}) + c_{2} sin (\frac{3 t}{5})

Schritte zur Lösung

25 y^{''} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{3 t}{5}) + c_{2} sin (\frac{3 t}{5})

y = c_{1} cos (\frac{3 t}{5}) + c_{2} sin (\frac{3 t}{5})

\int_{0}^{4} 2 π x (8 - x^{\frac{3}{2}}) d x

\int_{2}^{3} \frac{33}{3 - x} d x

\frac{d x}{d t} = e^{x} \cdot sin (t)

ma c l a u r in sin (\frac{x π}{4})

x \to \infty lim (\frac{1}{0})