derivative of ln((x^2-5^2/(x^2+5^2)))

Lösung

\frac{d}{d x} (ln (\frac{x ^{2} - 5 ^{2}}{x ^{2} + 5 ^{2}}))

\frac{100 x}{( x ^{2} - 25 ) ( x ^{2} + 25 )}

Schritte zur Lösung

\frac{d}{d x} (ln (\frac{x ^{2} - 5 ^{2}}{x ^{2} + 5 ^{2}}))

Vereinfache

ln (\frac{x ^{2} - 5 ^{2}}{x ^{2} + 5 ^{2}}) : ln (\frac{x ^{2} - 25}{x ^{2} + 25})

= \frac{d}{d x} (ln (\frac{x ^{2} - 25}{x ^{2} + 25}))

Wende die Kettenregel an:

\frac{1}{\frac{x ^{2} - 25}{x ^{2} + 25}} \frac{d}{d x} (\frac{x ^{2} - 25}{x ^{2} + 25})

= \frac{1}{\frac{x ^{2} - 25}{x ^{2} + 25}} \frac{d}{d x} (\frac{x ^{2} - 25}{x ^{2} + 25})

\frac{d}{d x} (\frac{x ^{2} - 25}{x ^{2} + 25}) = \frac{100 x}{( x ^{2} + 25 ) ^{2}}

= \frac{1}{\frac{x ^{2} - 25}{x ^{2} + 25}} \cdot \frac{100 x}{( x ^{2} + 25 ) ^{2}}

Vereinfache

\frac{1}{\frac{x ^{2} - 25}{x ^{2} + 25}} \cdot \frac{100 x}{( x ^{2} + 25 ) ^{2}} : \frac{100 x}{( x ^{2} - 25 ) ( x ^{2} + 25 )}

= \frac{100 x}{( x ^{2} - 25 ) ( x ^{2} + 25 )}

\int (7^{x - 2}) d x

in v erse l a pl a ce \frac{10 s}{s ^{2} + 16}

\int (sec^{2} (x) + 8) d x

\int 2 x x^{2} + 9 d x

\frac{d}{d x} ((2 x^{2} - 4 x)^{2})