What is the integral of (7^{x-2}) ?

The integral of (7^{x-2}) is (7^{x-2})/(ln(7))+C

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integral of (7^{x-2})

\int (7^{x - 2}) d x

\frac{7 ^{x - 2}}{ln ( 7 )} + C

Solution steps

\int 7^{x - 2} d x

Apply u-substitution

= \int 7^{u} d u

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{7 ^{u}}{ln ( 7 )}

Substitute back

u = x - 2

= \frac{7 ^{x - 2}}{ln ( 7 )}

Add a constant to the solution

= \frac{7 ^{x - 2}}{ln ( 7 )} + C

in v erse l a pl a ce \frac{10 s}{s ^{2} + 16}

\int (sec^{2} (x) + 8) d x

\int 2 x x^{2} + 9 d x

\frac{d}{d x} ((2 x^{2} - 4 x)^{2})

in v erse l a pl a ce \frac{3}{s s ^{2} + 8 ss + 18 s}

What is the integral of (7^{x-2}) ?
The integral of (7^{x-2}) is (7^{x-2})/(ln(7))+C