integral of 1/(X^2)

解答

\int \frac{1}{X ^{2}} d X

- \frac{1}{X} + C

求解步骤

\int \frac{1}{X ^{2}} d X

使用幂法则

= - \frac{1}{X}

解答补常数

= - \frac{1}{X} + C

\int \frac{5 x ^{2} - 12}{( x ^{2} - 6 x + 13 ) ^{2}} d x

\int \frac{4 x}{x ^{3} - x ^{2} - x + 1} d x

im pl i c i t y x = c

\frac{d}{d x} (\frac{4}{2 x + 5})

d er i v a t i v e ln (\frac{x - 5}{x - 4})