What is the derivative of (x^3-1^4) ?

The derivative of (x^3-1^4) is 12x^2(x^3-1)^3

What is the first derivative of (x^3-1^4) ?

The first derivative of (x^3-1^4) is 12x^2(x^3-1)^3

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\frac{d}{d x} ((x^{3} - 1)^{4})

12 x^{2} (x^{3} - 1)^{3}

Solution steps

\frac{d}{d x} ((x^{3} - 1)^{4})

Apply the chain rule:

4 (x^{3} - 1)^{3} \frac{d}{d x} (x^{3} - 1)

= 4 (x^{3} - 1)^{3} \frac{d}{d x} (x^{3} - 1)

\frac{d}{d x} (x^{3} - 1) = 3 x^{2}

= 4 (x^{3} - 1)^{3} \cdot 3 x^{2}

Simplify

= 12 x^{2} (x^{3} - 1)^{3}

\frac{\partial}{\partial x} (11 - 4 x^{2} - y^{2})

\frac{\partial}{\partial x} (2 x^{3} y^{2} cos (6 x^{3} y))

\int \frac{7}{sec ( x ) - 1} d x

\int \frac{e ^{2 x}}{e ^{5 - x}} d x

x \to \infty lim (67)

What is the derivative of (x^3-1^4) ?
The derivative of (x^3-1^4) is 12x^2(x^3-1)^3
What is the first derivative of (x^3-1^4) ?
The first derivative of (x^3-1^4) is 12x^2(x^3-1)^3