What is the derivative of sqrt(1+sec(2x)) ?

The derivative of sqrt(1+sec(2x)) is (sec(2x)tan(2x))/(sqrt(1+sec(2x)))

What is the first derivative of sqrt(1+sec(2x)) ?

The first derivative of sqrt(1+sec(2x)) is (sec(2x)tan(2x))/(sqrt(1+sec(2x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

1 + sec (2 x)

\frac{sec ( 2 x ) tan ( 2 x )}{1 + sec ( 2 x )}

Solution steps

\frac{d}{d x} (1 + sec (2 x))

Apply the chain rule:

\frac{1}{2 1 + sec ( 2 x )} \frac{d}{d x} (1 + sec (2 x))

= \frac{1}{2 1 + sec ( 2 x )} \frac{d}{d x} (1 + sec (2 x))

\frac{d}{d x} (1 + sec (2 x)) = 2 sec (2 x) tan (2 x)

= \frac{1}{2 1 + sec ( 2 x )} \cdot 2 sec (2 x) tan (2 x)

Simplify

\frac{1}{2 1 + sec ( 2 x )} \cdot 2 sec (2 x) tan (2 x) : \frac{sec ( 2 x ) tan ( 2 x )}{1 + sec ( 2 x )}

= \frac{sec ( 2 x ) tan ( 2 x )}{1 + sec ( 2 x )}

l a pl a ce t r an s f or m cos (θ)

x \to 0 lim (e^{x})

d er i v a t i v e y = \frac{1}{x ^{2} + 1}

\int - \frac{2}{9 - 9 x ^{2}} d x

x y^{^{'}} + 3 y = \frac{( 2 e ^{4 x} )}{x ^{2}}

What is the derivative of sqrt(1+sec(2x)) ?
The derivative of sqrt(1+sec(2x)) is (sec(2x)tan(2x))/(sqrt(1+sec(2x)))
What is the first derivative of sqrt(1+sec(2x)) ?
The first derivative of sqrt(1+sec(2x)) is (sec(2x)tan(2x))/(sqrt(1+sec(2x)))