What is laplacetransform cos(θ) ?

The answer to laplacetransform cos(θ) is s/(s^2+1)

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laplacetransform cos(θ)

laplace transform

cos (θ)

\frac{s}{s ^{2} + 1}

Solution steps

L {cos (θ)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (θ)} = \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1}

x \to 0 lim (e^{x})

d er i v a t i v e y = \frac{1}{x ^{2} + 1}

\int - \frac{2}{9 - 9 x ^{2}} d x

x y^{^{'}} + 3 y = \frac{( 2 e ^{4 x} )}{x ^{2}}

d er i v a t i v e y = \frac{1}{( 4 x ^{2} + 3 ) ^{5}}

What is laplacetransform cos(θ) ?
The answer to laplacetransform cos(θ) is s/(s^2+1)