What is the derivative of 2x^{0.5} ?

The derivative of 2x^{0.5} is 1/(x^{0.5)}

What is the first derivative of 2x^{0.5} ?

The first derivative of 2x^{0.5} is 1/(x^{0.5)}

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\frac{d}{d x} (2 x^{0.5})

\frac{1}{x ^{0.5}}

Solution steps

\frac{d}{d x} (2 x^{0.5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{0.5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 0.5 x^{0.5 - 1}

Simplify

2 \cdot 0.5 x^{0.5 - 1} : \frac{1}{x ^{0.5}}

= \frac{1}{x ^{0.5}}

\int 2 sin^{3} (x co) s^{7} x

t an g e n t f (x) = \frac{9}{x}, at x = 5

\frac{d}{d x} (\frac{2 x - 3}{x ^{2}})

n = 0 \sum \infty i^{n}

d er i v a t i v e (x + \frac{1}{x})^{4}

What is the derivative of 2x^{0.5} ?
The derivative of 2x^{0.5} is 1/(x^{0.5)}
What is the first derivative of 2x^{0.5} ?
The first derivative of 2x^{0.5} is 1/(x^{0.5)}