What is the derivative of (x+1/x)^4 ?

The derivative of (x+1/x)^4 is 4(x+1/x)^3(1-1/(x^2))

What is the first derivative of (x+1/x)^4 ?

The first derivative of (x+1/x)^4 is 4(x+1/x)^3(1-1/(x^2))

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derivative of

(x + \frac{1}{x})^{4}

4 (x + \frac{1}{x})^{3} (1 - \frac{1}{x ^{2}})

Solution steps

\frac{d}{d x} ((x + \frac{1}{x})^{4})

Apply the chain rule:

4 (x + \frac{1}{x})^{3} \frac{d}{d x} (x + \frac{1}{x})

= 4 (x + \frac{1}{x})^{3} \frac{d}{d x} (x + \frac{1}{x})

\frac{d}{d x} (x + \frac{1}{x}) = 1 - \frac{1}{x ^{2}}

= 4 (x + \frac{1}{x})^{3} (1 - \frac{1}{x ^{2}})

\frac{\partial}{\partial z} (x^{2} e^{y z^{2}})

\frac{d x}{d y} = 70 - 4 x

\int_{3}^{\infty} e^{- 7 x} d x

d er i v a t i v e y = - 6 x + k

\int_{0}^{1} 1 (x^{2} + 1) e^{- x} d x

What is the derivative of (x+1/x)^4 ?
The derivative of (x+1/x)^4 is 4(x+1/x)^3(1-1/(x^2))
What is the first derivative of (x+1/x)^4 ?
The first derivative of (x+1/x)^4 is 4(x+1/x)^3(1-1/(x^2))