y^{''}+y^'-6y=0,y(0)=5,y^'(0)=2

Lösung

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 5, y^{^{'}} (0) = 2

y = (5 - \frac{8}{5}) e^{2 t} + \frac{8}{5} e^{- 3 t}

Schritte zur Lösung

y^{''} (t) + y^{'} (t) - 6 y = 0

Solve linear ODE:

y = (5 - \frac{8}{5}) e^{2 t} + \frac{8}{5} e^{- 3 t}

y = (5 - \frac{8}{5}) e^{2 t} + \frac{8}{5} e^{- 3 t}

\int 5 x^{2} + 3 x + 2 d x

\int_{0}^{5} (1 + 2 x^{3}) d x

\frac{\partial}{\partial x} (x arctan (x + 2 y))

\frac{d}{d x} (\frac{2 cos ( x )}{x + 1})

\int \frac{( x - 2 )}{2} d x