integral from 0 to 5 of (1+2x^3)

解答

\int_{0}^{5} (1 + 2 x^{3}) d x

\frac{635}{2}

十进制

317.5

求解步骤

\int_{0}^{5} 1 + 2 x^{3} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 1 d x + \int_{0}^{5} 2 x^{3} d x

\int_{0}^{5} 1 d x = 5

\int_{0}^{5} 2 x^{3} d x = \frac{625}{2}

= 5 + \frac{625}{2}

化简

5 + \frac{625}{2} : \frac{635}{2}

= \frac{635}{2}

\frac{\partial}{\partial x} (x arctan (x + 2 y))

\frac{d}{d x} (\frac{2 cos ( x )}{x + 1})

\int \frac{( x - 2 )}{2} d x

\frac{d}{d x} (\frac{10 x}{x ^{2} - 6})

t an g e n t f (x) = x^{2} - 5, (- 3, 4)