What is the derivative of acos(2x+bsin(2x)) ?

The derivative of acos(2x+bsin(2x)) is -2asin(2x)+bcos(2x)*2

What is the first derivative of acos(2x+bsin(2x)) ?

The first derivative of acos(2x+bsin(2x)) is -2asin(2x)+bcos(2x)*2

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\frac{d}{d x} (a cos (2 x) + b sin (2 x))

- 2 a sin (2 x) + b cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (a cos (2 x) + b sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (2 x)) + \frac{d}{d x} (b sin (2 x))

\frac{d}{d x} (a cos (2 x)) = - 2 a sin (2 x)

\frac{d}{d x} (b sin (2 x)) = b cos (2 x) \cdot 2

= - 2 a sin (2 x) + b cos (2 x) \cdot 2

\frac{d}{d x} (a sin (x))

\int tan (2 x se) c^{2} 2 x d x

t an g e n t y = 3 x - 2 x^{2}, (- 3, - 27)

x \to 0 + lim (x + 1)

\frac{d y}{d x} = e^{2 y} sin (x)

What is the derivative of acos(2x+bsin(2x)) ?
The derivative of acos(2x+bsin(2x)) is -2asin(2x)+bcos(2x)*2
What is the first derivative of acos(2x+bsin(2x)) ?
The first derivative of acos(2x+bsin(2x)) is -2asin(2x)+bcos(2x)*2