What is the solution for (dy)/(dx)=e^{2y}sin(x) ?

The solution for (dy)/(dx)=e^{2y}sin(x) is y=-(ln(2cos(x)-c_{1}))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)=e^{2y}sin(x)

\frac{d y}{d x} = e^{2 y} sin (x)

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{2 y} sin (x)

Solve separable ODE:

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

n = 1 \sum \infty \frac{x ^{n}}{1 0 ^{n}}

\int_{0}^{1} 36 t^{2} + 9 t^{4} d t

y^{^{'}} = \frac{sin ( 2 x )}{e ^{y}}

\frac{d}{d x} (\frac{e ^{x}}{4 x ^{2} + 1})

\int e^{x} cos (4 y) d x

What is the solution for (dy)/(dx)=e^{2y}sin(x) ?
The solution for (dy)/(dx)=e^{2y}sin(x) is y=-(ln(2cos(x)-c_{1}))/2