10y^'+5y=8e^{6x},y(0)=9

Lösung

10 y^{^{'}} + 5 y = 8 e^{6 x}, y (0) = 9

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

Schritte zur Lösung

10 y^{'} (x) + 5 y = 8 e^{6 x}

Solve linear ODE:

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

x \to 3 lim (\frac{∣ x ∣ - x}{3 - x})

y^{^{''}} + (y^{^{'}})^{2} + 1 = 0

\int_{- 40}^{0} \frac{1}{9 - x} d x

a re a \frac{1}{8} x, 8 x, \frac{2}{x}

\int_{2}^{8} \frac{5}{4 - 3 x} d x