What is the integral of 4/u ?

The integral of 4/u is 4ln|u|+C

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integral of 4/u

\int \frac{4}{u} d u

4 ln ∣ u ∣ + C

Solution steps

\int \frac{4}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 4 ln ∣ u ∣

Add a constant to the solution

= 4 ln ∣ u ∣ + C

n = 2 \sum \infty e^{5 - 2 n}

\int - 16 x d x

\int (x + 1)^{10} (x + 2) d x

d er i v a t i v e y = ln (sec (x))

x \to 0 lim ((\frac{1}{x})^{x^{2}})