What is the derivative of y=ln(sec(x)) ?

The derivative of y=ln(sec(x)) is tan(x)

What is the first derivative of y=ln(sec(x)) ?

The first derivative of y=ln(sec(x)) is tan(x)

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derivative of

y = ln (sec (x))

tan (x)

Solution steps

\frac{d}{d x} (ln (sec (x)))

Apply the chain rule:

\frac{1}{sec ( x )} \frac{d}{d x} (sec (x))

= \frac{1}{sec ( x )} \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= \frac{1}{sec ( x )} sec (x) tan (x)

Simplify

\frac{1}{sec ( x )} sec (x) tan (x) : tan (x)

= tan (x)

x \to 0 lim ((\frac{1}{x})^{x^{2}})

\frac{d}{d x} (e^{- 2 x} (a cos (x) + b sin (x)))

x \to 0 + lim (\frac{6}{sin ( x )})

\frac{d y}{d x} + x y = y

\frac{d}{d x} (cot (7 x))

What is the derivative of y=ln(sec(x)) ?
The derivative of y=ln(sec(x)) is tan(x)
What is the first derivative of y=ln(sec(x)) ?
The first derivative of y=ln(sec(x)) is tan(x)