What is the limit as x approaches 1+of arcsin(x) ?

The limit as x approaches 1+of arcsin(x) is pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 1+of arcsin(x)

x \to 1 + lim (arcsin (x))

\frac{π}{2}

Decimal

1.57079 \dots

Solution steps

x \to 1 + lim (arcsin (x))

Plug in the value

x = 1

= arcsin (1)

Use the following trivial identity:

arcsin (1) = \frac{π}{2}

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

\frac{d}{d x} (e^{2 x} (3 x - 2))

e x p an d (x^{3} - 4 x^{2} - 6 x + 1) (x^{2} - 3 x + 1)

\frac{d}{d x} (- sin (2 x) + 1)

\frac{d}{d x} ((5 x - 3) (4 x - \frac{3}{x}))

\int \frac{x ^{2}}{x ^{3} + 9} d x

What is the limit as x approaches 1+of arcsin(x) ?
The limit as x approaches 1+of arcsin(x) is pi/2