What is the derivative of-sin(2x+1) ?

The derivative of-sin(2x+1) is -2cos(2x)

What is the first derivative of-sin(2x+1) ?

The first derivative of-sin(2x+1) is -2cos(2x)

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\frac{d}{d x} (- sin (2 x) + 1)

- 2 cos (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x)) + \frac{d}{d x} (1)

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

\frac{d}{d x} (1) = 0

= - cos (2 x) \cdot 2 + 0

Simplify

= - 2 cos (2 x)

\frac{d}{d x} ((5 x - 3) (4 x - \frac{3}{x}))

\int \frac{x ^{2}}{x ^{3} + 9} d x

\frac{d}{d x} (9 x^{2} e^{x})

\frac{d}{d x} (x sinh (x) - cosh (x))

\int \frac{3 x}{x ^{2} + 5} d x

What is the derivative of-sin(2x+1) ?
The derivative of-sin(2x+1) is -2cos(2x)
What is the first derivative of-sin(2x+1) ?
The first derivative of-sin(2x+1) is -2cos(2x)