What is the tangent of f(x)=x^4-17x^2+16,\at x=-2 ?

The tangent of f(x)=x^4-17x^2+16,\at x=-2 is y=36x+36

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tangent of f(x)=x^4-17x^2+16,\at x=-2

tangent of

f (x) = x^{4} - 17 x^{2} + 16, at x = - 2

y = 36 x + 36

Solution steps

Find the tangent point:

(- 2, - 36)

Find the slope of

f (x) = x^{4} - 17 x^{2} + 16 : \frac{df ( x )}{d x} = 4 x^{3} - 34 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 36

Find the line with slope m=

36

and passing through

(- 2, - 36) : y = 36 x + 36

y = 36 x + 36

d er i v a t i v e \frac{- 5}{x ^{6}}

\int (1 + x^{2}) (2 x) d x

d er i v a t i v e sec (6 x)

n = 1 \sum \infty \frac{3}{( n + 1 ) !}

x \to 0 lim (\frac{3}{x} - \frac{3}{x ^{2} + x})

What is the tangent of f(x)=x^4-17x^2+16,\at x=-2 ?
The tangent of f(x)=x^4-17x^2+16,\at x=-2 is y=36x+36