What is the solution for y^{''}-4y^'-5y=9e^{2t} ?

The solution for y^{''}-4y^'-5y=9e^{2t} is y=c_{1}e^{5t}+c_{2}e^{-t}-e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-4y^'-5y=9e^{2t}

y^{^{''}} - 4 y^{^{'}} - 5 y = 9 e^{2 t}

y = c_{1} e^{5 t} + c_{2} e^{- t} - e^{2 t}

Solution steps

y^{''} (t) - 4 y^{'} (t) - 5 y = 9 e^{2 t}

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{- t} - e^{2 t}

y = c_{1} e^{5 t} + c_{2} e^{- t} - e^{2 t}

\frac{d ^{2}}{d x ^{2}} (3 x^{2} e^{x})

\int sec (2)

\frac{d}{d y} (x \cdot y^{2})

\frac{d}{d t} (- a sin (t) + b cos (t))

x \to 0 lim ((tan (8 x))^{x})

What is the solution for y^{''}-4y^'-5y=9e^{2t} ?
The solution for y^{''}-4y^'-5y=9e^{2t} is y=c_{1}e^{5t}+c_{2}e^{-t}-e^{2t}