(\partial)/(\partial y)((ax+by)/(cx+dy))

解答

\frac{\partial}{\partial y} (\frac{a x + b y}{c x + d y})

\frac{x b c - a x d}{( x c + y d ) ^{2}}

求解步骤

\frac{\partial}{\partial y} (\frac{a x + b y}{c x + d y})

将

a, x, b, c, d

视为常数

使用微分除法定则:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial y} ( a x + b y ) ( c x + d y ) - \frac{\partial}{\partial y} ( c x + d y ) ( a x + b y )}{( c x + d y ) ^{2}}

\frac{\partial}{\partial y} (a x + b y) = b

\frac{\partial}{\partial y} (c x + d y) = d

= \frac{b ( c x + d y ) - d ( a x + b y )}{( c x + d y ) ^{2}}

乘开

b (c x + d y) - d (a x + b y) : x b c - a x d

= \frac{x b c - a x d}{( x c + y d ) ^{2}}

\int \frac{cos ^{3} ( x )}{1 + sin ( x )} d x

\int \frac{1}{x ^{2} - 100} d x

\int \frac{x}{1 - 16 x ^{2}} d x

\frac{d}{d x} (2 sin (x) - sin (2 x))

\frac{d}{d x} (\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}})