What is the integral from 0 to 0.6 of 500x ?

The integral from 0 to 0.6 of 500x is 90

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integral from 0 to 0.6 of 500x

\int_{0}^{0.6} 500 x d x

90

Solution steps

\int_{0}^{0.6} 500 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 500 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

= 500 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 500 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 500 \cdot 0.18

Simplify

= 90

d er i v a t i v e (8 x^{3} - 5 x + 2)^{π}

t an g e n t y = \frac{1 + x}{1 + e ^{x}}, (0, \frac{1}{2})

x \to 0 + lim (3 x ln (x))

d er i v a t i v e 3 x ln (15 x)

a re a x^{2} + 2 x + 1, 2 x + 5, [- 2, 2]

What is the integral from 0 to 0.6 of 500x ?
The integral from 0 to 0.6 of 500x is 90