What is area x^2+2x+1,2x+5,[-2,2] ?

The answer to area x^2+2x+1,2x+5,[-2,2] is 32/3

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area x^2+2x+1,2x+5,[-2,2]

area

x^{2} + 2 x + 1, 2 x + 5, [- 2, 2]

\frac{32}{3}

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x

Solve

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

d er i v a t i v e f (x) = 2 lo g_{5} (x)

\int \frac{8}{2 + 8 x} d x

d er i v a t i v e 10 6 x^{9} + 9 x^{6}

x \to 2 - lim (\frac{x ^{2}}{x ^{2} - 4})

\frac{\partial}{\partial y} (x e^{y} - y e^{x})

What is area x^2+2x+1,2x+5,[-2,2] ?
The answer to area x^2+2x+1,2x+5,[-2,2] is 32/3