What is the solution for (y^3-xy^2)dx+2x^2ydy=0 ?

The solution for (y^3-xy^2)dx+2x^2ydy=0 is y=(x(1+c_{1}sqrt(x)))/(c_{1)^2x-1}

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(y^3-xy^2)dx+2x^2ydy=0

(y^{3} - x y^{2}) d x + 2 x^{2} y d y = 0

y = \frac{x ( 1 + c _{1} x )}{c _{1}^{2} x - 1}

Solution steps

(y^{3} - x y^{2}) d x + 2 x^{2} y d y = 0

Solve Bernoulli ODE:

y = \frac{x ( 1 + c _{1} x )}{c _{1}^{2} x - 1}

y = \frac{x ( 1 + c _{1} x )}{c _{1}^{2} x - 1}

x \to 4 lim (6 - 3 x)

\frac{d}{d x} (c cos (t) + t^{2}, t)

\frac{d}{d x} (arcsec (e^{3 x}))

t an g e n t f (x) = - 3 + (x + 4)^{2}, at x = - 5

\frac{d}{d x} (e^{\frac{x ^{2}}{2 a}})

What is the solution for (y^3-xy^2)dx+2x^2ydy=0 ?
The solution for (y^3-xy^2)dx+2x^2ydy=0 is y=(x(1+c_{1}sqrt(x)))/(c_{1)^2x-1}